document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1034056>Question 1034056</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a hypotenuse of a right triangle is 10cm, one of the legs is 5cm long. Find the length of the other leg </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648669 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648669\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We use the Pythagorean Theorem<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2+%2B+b%5E2+=+c%5E2 ALIGN=MIDDLE  ALT=\"a%5E2+%2B+b%5E2+=+c%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "and we are looking for side b...so<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E2+=+c%5E2+-+a%5E2+=+10%5E2+-+5%5E2+=+100+-+25+=+75 ALIGN=MIDDLE  ALT=\"b%5E2+=+c%5E2+-+a%5E2+=+10%5E2+-+5%5E2+=+100+-+25+=+75\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=B+=+sqrt%2875%29+=+5%2Asqrt%283%29 ALIGN=MIDDLE  ALT=\"B+=+sqrt%2875%29+=+5%2Asqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "or about 8.66 cm. </SPAN>\n" );
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