document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1034043>Question 1034043</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The manager of a store selling tea plans to make a mix using a mix of a more expensive tea that costs $8 per pound and a less expensive tea that costs $3 per pound to create a 130- pound blend that will sell for 5$ a pound how many of each type are required>? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648642 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648642\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the amount of $8 tea, x.<BR>\n" );
document.write( "Then the amount of $3 tea would be 130-x.<BR>\n" );
document.write( "The setup looks like this:<BR>\n" );
document.write( "8x + 3(130-x) = 5(130)<BR>\n" );
document.write( "Now solve for x...<BR>\n" );
document.write( "8x + 390 - 3x = 650<BR>\n" );
document.write( "5x = 260<BR>\n" );
document.write( "x = 52 lbs @ $8 so that<BR>\n" );
document.write( "130-x = 78 lbs @ $3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );