document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1034031>Question 1034031</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jana invests £300 at a simple interest rate at 4.5% per year.at the end of each year jane gives the interst to a charit. <BR>\n" );
document.write( "work out the least number of years it will take for the total amount given to th charity to be greater than £50. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648637 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648637\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Simple interest is given by<BR>\n" );
document.write( "I = Prt<BR>\n" );
document.write( "so here, one year's interest is<BR>\n" );
document.write( "I = 300(.045) = £13.5<BR>\n" );
document.write( "Divide 50 by 13.5 and get 3.7 years...thus<BR>\n" );
document.write( "she will need four years to donate £50... </SPAN>\n" );
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