document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1034029>Question 1034029</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write an equation of the line passing through the point (6,5) and perpendicular to the line whose equation is 2y+3x=6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648623 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648623\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If we find the slope of<BR>\n" );
document.write( "2y+3x=6<BR>\n" );
document.write( "we can do that by solving for y...<BR>\n" );
document.write( "2y = -3x + 6<BR>\n" );
document.write( "y = (-3/2)x + 3<BR>\n" );
document.write( "Since we want a perpendicular line, the slope we need is 2/3.<BR>\n" );
document.write( "Now plug in to y = mx + b to find b...<BR>\n" );
document.write( "5 = (2/3)(6) + b<BR>\n" );
document.write( "5 = 4 + b<BR>\n" );
document.write( "b = 1<BR>\n" );
document.write( "so the line we want is<BR>\n" );
document.write( "y = (2/3)x + 1 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );