document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1034025>Question 1034025</A>: <I><SPAN STYLE=\"word-break: break-all;\"> She needs to prepare 24 ounces of a 10&#8203;% hydrochloric acid solution. Find the amount of 12&#8203;% solution and the amount of 6&#8203;% solution she should mix to get this solution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648616 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648616\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's call the amount of 12% used, x.<BR>\n" );
document.write( "Then the amount of 6% used would have to be 24-x (since we need 24 ounces total).<BR>\n" );
document.write( "Here's the set up...<BR>\n" );
document.write( ".12x + .06(24-x) = .10(24)<BR>\n" );
document.write( "Now solve for x...<BR>\n" );
document.write( ".12x + 1.44 - .06x = 2.4<BR>\n" );
document.write( ".06x = .96<BR>\n" );
document.write( "x = 16 ounces of 12%<BR>\n" );
document.write( "24-x = 8 ounces of 6% </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );