document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033968>Question 1033968</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When an angle is added to twice its complement and thrice its supplement, it exceeds the original angle by 490°. Find the angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648605 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648605\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the measure of the angle you need, x.<BR>\n" );
document.write( "Its complement is 90-x.<BR>\n" );
document.write( "Its supplement is 180-x.<BR>\n" );
document.write( "Then we write<BR>\n" );
document.write( "x + 2(90-x) + 3(180-x) = x + 490<BR>\n" );
document.write( "Now solve for x...<BR>\n" );
document.write( "x + 180 - 2x + 540 - 3x = x + 490<BR>\n" );
document.write( "subtract the x, combine the rest...<BR>\n" );
document.write( "720 - 5x = 490<BR>\n" );
document.write( "subtract 720 and divide by -5<BR>\n" );
document.write( "-5x = -230<BR>\n" );
document.write( "x = 46 degrees </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );