document.write( "Question 12840: I am an older student in Algebra and it is sooooooo confusing. I am having trouble with order of operations. Can you help me with this problem?:
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document.write( "7(3x-2)+5=6(2x-1)+24
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document.write( "this is what I have tried:
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document.write( "21x-14+5=12x-6+24
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document.write( "21x-9=12x+18
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document.write( "9x=-9+18
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document.write( "9x=9
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document.write( "x=1\r
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document.write( "But it's not right when I check it-but I may be doing that wrong also. Thank you for any help! \n" );
document.write( "
Algebra.Com's Answer #6486 by elima(1433) ![]() You can put this solution on YOUR website! You were on the right track till you you got to the step of subtracting the 9 from both sides. \n" ); document.write( "You have 21x-9=12x+18 \n" ); document.write( "Which actually is 21x+(-9)=12x+18 \n" ); document.write( "Remember to get rid of the 9 and make it a zero you need to add a POSITIVE 9 to both sides. \n" ); document.write( "So you get: 21x-9+9=12x+18+9 \n" ); document.write( "This cancels out the 9 from the left side; \n" ); document.write( "21x=12x+18+9; \n" ); document.write( "21x-12x=27 \n" ); document.write( "9x=27 \n" ); document.write( "x=3 \n" ); document.write( "Hope this helps you with your algebra, it really isn't that difficult. \n" ); document.write( "=) \n" ); document.write( " |