document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033843>Question 1033843</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A radioactive isotope has a decay rate of 2% per year. Calculate the half-life for this isotope, using the exact half-life formula. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648471 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648471\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
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document.write( "N(t)=Noe^(-Lt)<BR>\n" );
document.write( "(1/2)=e^(-.02t)<BR>\n" );
document.write( "ln both sides<BR>\n" );
document.write( "-ln2=-.02t<BR>\n" );
document.write( "ln 2=.02t<BR>\n" );
document.write( "ln2/.02=34.66 years </SPAN>\n" );
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