document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033789>Question 1033789</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the inequality and express the solution using interval notation\r<BR>\n" );
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document.write( "x^2-7x+12>0<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648449 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648449\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If we analyze<BR>\n" );
document.write( "x^2-7x+12>0<BR>\n" );
document.write( "we start by factoring it..we get<BR>\n" );
document.write( "(x-3)(x-4) > 0<BR>\n" );
document.write( "For us to have a product greater than zero, both factors have to be positive or both have to be negative...<BR>\n" );
document.write( "For both to be positive, x has to be greater than 4.<BR>\n" );
document.write( "For both to be negative, x has to be less than 3.<BR>\n" );
document.write( "In interval notation, it looks like<BR>\n" );
document.write( "(-infinity, 3) U (4, infinity) </SPAN>\n" );
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