document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033765>Question 1033765</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in a circle of radius 96.4 inches, what is the central angle that subtends a stand of 40.3 inches?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648439 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648439\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is an arc length problem.<BR>\n" );
document.write( "The formula for these is<BR>\n" );
document.write( "Arc length = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28%28theta%29%2F360%29%2A2%28pi%29r ALIGN=MIDDLE  ALT=\"%28%28theta%29%2F360%29%2A2%28pi%29r\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Plugging in what we know, we look for theta...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=40.3+=+%28%28theta%29%2F360%29+%2A+%282%2Api%2A96.4%29 ALIGN=MIDDLE  ALT=\"40.3+=+%28%28theta%29%2F360%29+%2A+%282%2Api%2A96.4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "If you do that calculation carefully, see if you can get<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=theta+=+23.95 ALIGN=MIDDLE  ALT=\"theta+=+23.95\"   DISABLED_style= \"max-width:90%; height:auto;\" > degrees </SPAN>\n" );
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