document.write( "Question 1033620: 1/3 log3 x^6 +1/6 log3 x^6 - 1/9 log3x
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Algebra.Com's Answer #648419 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
1/3 * log3(x^6) + 1/6 * log3(x^6) - 1/9 * log3(x) is your expression.\r
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\n" ); document.write( "\n" ); document.write( "since 1/3 * log3(x^6) is equivalent to log3((x^6)^(1/3)) which is equal to log3(x^2), ...\r
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\n" ); document.write( "\n" ); document.write( "and since 1/6 * log3(x^6) is equivalent to log3((x^6)^(1/6)) which is equal to log3(x), ...\r
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\n" ); document.write( "\n" ); document.write( "and since 1/9 * log3(x) is equivalent to log3((x^(1/9)) which is equal to log3(x^(1/9)), your expression becomes ...\r
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\n" ); document.write( "\n" ); document.write( "log3(x^2) + log3(x) - log3(x^(1/9).\r
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\n" ); document.write( "\n" ); document.write( "since log3(x^2) + log3(x) is equivalent to log3(x^2*x) which is equal to log3(x^3), your expression becomes ...\r
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\n" ); document.write( "\n" ); document.write( "log3(x^3) - log3(x^(1/9)).\r
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\n" ); document.write( "\n" ); document.write( "since log3(x^3) - log3(x^(1/9)) is equivalent to log3(x^3 / x^(1/9)) which is equal to log3(x^(26/9), your expression becomes ...\r
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\n" ); document.write( "\n" ); document.write( "log3(x^(26/9).\r
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\n" ); document.write( "\n" ); document.write( "i believe that's as simple as it gets.\r
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\n" ); document.write( "\n" ); document.write( "you can confirm that your solution is correct by assigning a random value to x and then evaluating the original expression and the final expression to see that they give you the same answer.\r
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\n" ); document.write( "\n" ); document.write( "i chose x = 5 and i got the same answer for both the original expression and the final expression.
\n" ); document.write( "my answer was 4.232145727.
\n" ); document.write( "it helps to use the log conversion formula.
\n" ); document.write( "log3(x) = log10(x) / log10(3).
\n" ); document.write( "this allows you to use your calculator since the calculator log function assumes log10.
\n" ); document.write( "using your calculator, you would simply enter log3(x) as log(x) / log(3).
\n" ); document.write( "for the final expression, i entered log3(x^(26/9)) as log(5^(26/9)) / log(3).
\n" ); document.write( "for the original expression, i entered 1/3 * log3(x^6) + 1/6 * log3(x^6) - 1/9 * log3(x) as (1/3 * log(5^6) + 1/6 * log(5^6) - 1/9 * log(5)) / log(3).\r
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