document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=89207>Question 89207</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the solution sets for\r<BR>\n" );
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document.write( "2x^2+3x-5=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64839 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64839\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x^2 + 3x - 5 = 0<BR>\n" );
document.write( "2x^2 + 5x - 2x - 5 = 0  ...   being 5 and -2 are factors of 2*-5 that sum to 3<BR>\n" );
document.write( "(2x^2 + 5x) + (-2x - 5) = 0<BR>\n" );
document.write( "x(2x + 5) - (2x + 5) = 0<BR>\n" );
document.write( "(x - 1)(2x + 5) = 0<BR>\n" );
document.write( "x = 1 and x = -5/2 </SPAN>\n" );
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