document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033712>Question 1033712</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bus is 13 miles from town traveling 80 miles an hour.  A car leaves town at the same moment going the same direction as the bus at the same speed.  The question is:  After how long will the bus's distance from town be twice the car's distance?  Thus far I have done the following:  <BR>\n" );
document.write( "x= hours bus and car travel<BR>\n" );
document.write( "80x= distance car travels<BR>\n" );
document.write( "13+80x=distance bus travels<BR>\n" );
document.write( "I am having difficulty setting up the equation....for some reason I cannot \"see\" the solution.  Thank you.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648383 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648383\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> b= bus<BR>\n" );
document.write( "c= car<BR>\n" );
document.write( "c = 80x <BR>\n" );
document.write( "b = 13+80x<BR>\n" );
document.write( "find b = 2c<BR>\n" );
document.write( "`````````````````````````````````<BR>\n" );
document.write( "13+80x = 2*80x<BR>\n" );
document.write( "13+80x = 160x subtract 80x from both sides and flip the equation to get the unknown on the left side -it looks better:<BR>\n" );
document.write( "80x = 13<BR>\n" );
document.write( "x = 13/80 = 0.1625 hours; 0.1625*60 = 9.75 minutes = 9 minutes and 45 seconds<BR>\n" );
document.write( "John </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );