document.write( "Question 1033712: A bus is 13 miles from town traveling 80 miles an hour. A car leaves town at the same moment going the same direction as the bus at the same speed. The question is: After how long will the bus's distance from town be twice the car's distance? Thus far I have done the following:
\n" ); document.write( "x= hours bus and car travel
\n" ); document.write( "80x= distance car travels
\n" ); document.write( "13+80x=distance bus travels
\n" ); document.write( "I am having difficulty setting up the equation....for some reason I cannot \"see\" the solution. Thank you.
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Algebra.Com's Answer #648382 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Try to draw a picture and form a data table.\r
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document.write( "            rate     time        distance moved\r\n" );
document.write( "BUS         80         t           d               80t=d\r\n" );
document.write( "CAR         80         t           d               80t=d\r\n" );
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\n" ); document.write( "\n" ); document.write( "t is used for both because this is the same time quantity.\r
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\n" ); document.write( "\n" ); document.write( "Bus distance from the town becomes 80t+13.
\n" ); document.write( "Car distance from the town becomes 80t.
\n" ); document.write( "Review all of this a few times with concentration so you understand.\r
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\n" ); document.write( "When that makes sense, look at the question.
\n" ); document.write( "How much time t for the bus to be twice the car, FROM THE TOWN?\r
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\n" ); document.write( "\n" ); document.write( "\"80t%2B13=2%2880t%29\"
\n" ); document.write( "Again, review all of this including this equation so that it also makes sense for you.\r
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\n" ); document.write( "\n" ); document.write( "You want to solve for t, in this last equation.
\n" ); document.write( "\"80t%2B13=2%2A80t\"
\n" ); document.write( "\"80t%2B13-80t=2%2A80t-80t\"
\n" ); document.write( "\"13=80t\"
\n" ); document.write( "\"13%2F80=t\"------this is fraction of an hour, so you can convert to minutes if you want.
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