document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033689>Question 1033689</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The equation <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2+%2B+y%5E2+-+2x+%2B+8y+%2B+8+=+0 ALIGN=MIDDLE  ALT=\"x%5E2+%2B+y%5E2+-+2x+%2B+8y+%2B+8+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > is the equation of a circle. Complete the square to change this equation to standard form. Find the radius and the coordinates of the center of the circle. \r<BR>\n" );
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document.write( "Not sure what the first step would be to solve this problem. Any help would be great. Thank you :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648356 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648356\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2 + y^2 - 2x + 8y + 8 = 0<BR>\n" );
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document.write( "Rearrange::<BR>\n" );
document.write( "x^2 - 2x   + y^2 + 8y  = -8<BR>\n" );
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document.write( "Complete the square on the x-terms and on the y-terms ::<BR>\n" );
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document.write( "x^2 - 2x +1 + y^2 + 8y + 16 = -8 + 1 + 16<BR>\n" );
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document.write( "(x-1)^2 + (y+4)^2 = 9<BR>\n" );
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document.write( "Center:: (1,-4)<BR>\n" );
document.write( "radius:: sqrt(9) = 3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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