document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033656>Question 1033656</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is sec of 225 degrees? I understand that its like -1.4 or something but I don't understand how to get there. Could you walk me through it?<BR>\n" );
document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648319 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648319\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The way I teach it is first to write that<BR>\n" );
document.write( "sec 225 = 1/cos 225<BR>\n" );
document.write( "Then look for the value of cos 225.<BR>\n" );
document.write( "The reference angle is 45 degrees.<BR>\n" );
document.write( "In the third quadrant, cosine is negative.<BR>\n" );
document.write( "Thus cos 225 = -cos 45 = -sqrt(2)/2 which means<BR>\n" );
document.write( "sec 225 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-2%2Fsqrt%282%29+=+-sqrt%282%29 ALIGN=MIDDLE  ALT=\"-2%2Fsqrt%282%29+=+-sqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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