document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033667>Question 1033667</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I graph y=2x+5 and y-4x=-2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648318 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648318\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To graph any line in slope-intercept form, y = mx + b,<BR>\n" );
document.write( "you first plot a point at the y-intercept...<BR>\n" );
document.write( "For y = 2x + 5, that would be at the point (0,5).<BR>\n" );
document.write( "From that point you apply the slope...here that is 2 (which is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F1 ALIGN=MIDDLE  ALT=\"2%2F1\"   DISABLED_style= \"max-width:90%; height:auto;\" >), so you go up two points and go to the right one, thus plotting another point at (1,3)...then repeat and plot a point at (2,1)...then connect them into a line...<BR>\n" );
document.write( "For y - 4x = -2, add 4x to both sides and get y = 4x - 2 and repeat what I showed you above... </SPAN>\n" );
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