document.write( "Question 1033654: solve the equation $\"+3%5E2x+=+2%5Ex-1.\"$ round your answer to 3 decimal places
\n" ); document.write( "please show me how to work this out because I am stuck\r
\n" ); document.write( "\n" ); document.write( "also the exponent for 3 is 2x
\n" ); document.write( "the exponent for 2 is x-1 \n" ); document.write( "

Algebra.Com's Answer #648316 by Alan3354(69443) $\"\"$ $\"About$

You can put this solution on YOUR website!
solve the equation $\"+3%5E2x+=+2%5Ex-1.\"$ round your answer to 3 decimal places
\n" ); document.write( "please show me how to work this out because I am stuck\r
\n" ); document.write( "\n" ); document.write( "also the exponent for 3 is 2x
\n" ); document.write( "the exponent for 2 is x-1
\n" ); document.write( "================
\n" ); document.write( " $\"+3%5E%282x%29+=+2%5E%28x-1%29\"$
\n" ); document.write( "2x*log(3) = (x-1)*log(2) = x*log(2) - log(2)
\n" ); document.write( "2x*log(3) - x*log(2) = -log(2)
\n" ); document.write( "x*(2log(3) - log(2)) = -log(2)
\n" ); document.write( "x = log(2)/(log(2 - log(9))
\n" ); document.write( "===============
\n" ); document.write( "x =~ -0.460845
\n" ); document.write( " \n" ); document.write( "

\n" );