document.write( "Question 1033663: Bag A contains 15 marbles of which 8 are red and the rest are black. Bag B contains 14 marbles of which 4 are red 3 are blue and the rest are black. A ball is drawn at random first from bad A, and second from bag B. If we make the random variable be black marbles (B) complete the following.\r
\n" ); document.write( "\n" ); document.write( "A) Create a tree diagram:\r
\n" ); document.write( "\n" ); document.write( "B) complete a probability table for the number of black marbles
\n" ); document.write( "

Algebra.Com's Answer #648314 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
===8/14 red===========6/14 black
\n" ); document.write( "4/7 red====3/7 black ===4/7 red=====3/7 black
\n" ); document.write( "Probability of both black marbles is (3/7)(3/7)=9/49
\n" ); document.write( "probability of one black marble is (8/14)(3/7)+(6/14)(4/7)=24/49
\n" ); document.write( "probability of zero black marbles is (8/14)(4/7)=16/49
\n" ); document.write( "
\n" );