document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033650>Question 1033650</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Having a hard time figuring out this equation in a simplified fraction form.\r<BR>\n" );
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document.write( "0.19x+0.2(x-4)=0.01(3x-5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648306 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648306\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The easiest way out of these is to multiply everything by the lowest common denominator...here that is 100...so from<BR>\n" );
document.write( "0.19x+0.2(x-4)=0.01(3x-5)<BR>\n" );
document.write( "we multiply by 100 and get<BR>\n" );
document.write( "19x + 20(x-4) = 3x - 5<BR>\n" );
document.write( "19x + 20x - 80 = 3x - 5<BR>\n" );
document.write( "39x - 80 = 3x -5<BR>\n" );
document.write( "36x = 75<BR>\n" );
document.write( "x = 75/36 = 25/12 </SPAN>\n" );
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