document.write( "Question 1033621: the sum of a students three scores is 220. if the first is 23 points more than the second, and the sum of the first two is 31 more than twice the third what was the first score \n" ); document.write( "
Algebra.Com's Answer #648302 by fractalier(6550)\"\" \"About 
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A couple of ways to solve this...but let's call the three test scores, x, y and z. Then we can write
\n" ); document.write( "x + y + z = 220
\n" ); document.write( "x = y + 23
\n" ); document.write( "x + y = 31 + 2z
\n" ); document.write( "Let us then substitute the third one into the first one and get
\n" ); document.write( "31+2z + z = 220
\n" ); document.write( "3z + 31 = 220
\n" ); document.write( "3z = 189
\n" ); document.write( "z = 63
\n" ); document.write( "Now substitute the second equation into the first, including 63 for z...
\n" ); document.write( "y+23 + y + 63 = 220
\n" ); document.write( "2y + 86 = 220
\n" ); document.write( "2y = 134
\n" ); document.write( "y = 67
\n" ); document.write( "and since x = y + 23,
\n" ); document.write( "x = 90
\n" ); document.write( "Thus the scores were 90, 67, and 63. \n" ); document.write( "
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