document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1032663>Question 1032663</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Allen wants to buy a car that costs 17500. He already has 11,000. If he invests this at a simple interest rate of 2.3% how long will he need to invest until he has enough for the car? \r<BR>\n" );
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document.write( "Need asap!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648290 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648290\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> He will need to earn 17500 - 11000 = $6500 interest.<BR>\n" );
document.write( "The formula for this is<BR>\n" );
document.write( "I = Prt<BR>\n" );
document.write( "so we plug in and solve for the time, t...<BR>\n" );
document.write( "t = I / Pr = 6500 / (11000*.023) = 25.7 years<BR>\n" );
document.write( "(I'd get a second job.) </SPAN>\n" );
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