document.write( "Question 1033626: How many millilitres of water must be added to 240 milliliters of a 25% sulphuric acid solution to reduce the percentage of sulphuric acid in the new solution to 10%? \n" ); document.write( "
Algebra.Com's Answer #648278 by ikleyn(52802)\"\" \"About 
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\n" ); document.write( "How many milliliters of water must be added to 240 milliliters of a 25% sulphuric acid solution to reduce the percentage of sulphuric acid in the new solution to 10%?
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\n" ); document.write( "\n" ); document.write( "240*0.25 = (x+240)*0.10
\n" ); document.write( "60 = 0.1x + 24
\n" ); document.write( "0.1x = 60 - 24 = 36
\n" ); document.write( "x = 360 milliliters of water must be added.\r
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