document.write( "Question 1033455: Given: ABCD is a parallelogram Prove: KM x LB = LM x KD\r
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\n" ); document.write( "\n" ); document.write( "......... B------------------L-------C
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\n" ); document.write( "......./----------------M----------/
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\n" ); document.write( ".....A---------K-----------------D\r
\n" ); document.write( "\n" ); document.write( "The Labels are located like so, but I have no idea what the question means and how to go on and prove it
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Algebra.Com's Answer #648269 by mananth(16949)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "triangles LMB and KMD are similar\r
\n" ); document.write( "\n" ); document.write( "By AAA test of similarity\r
\n" ); document.write( "\n" ); document.write( "Alternate angles and vertically opposite angle\r
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\n" ); document.write( "\n" ); document.write( "KM/LM = KD/LB\r
\n" ); document.write( "\n" ); document.write( "Therefore KM * LB = LM * KD\r
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