document.write( "Question 1033626: How many millilitres of water must be added to 240 milliliters of a 25% sulphuric acid solution to reduce the percentage of sulphuric acid in the new solution to 10%? \n" ); document.write( "
Algebra.Com's Answer #648265 by mananth(16946)\"\" \"About 
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\n" ); document.write( "-------------- percent ---------------- Amount
\n" ); document.write( "Solution I 25 ---------------- 240 ml
\n" ); document.write( "Water 0 ---------------- x ml
\n" ); document.write( "Mixture 10 ---------------- 240 + x ml
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\n" ); document.write( "25 * 240 + 0 x = 10 ( 240 + x )
\n" ); document.write( "6000 + 0 x = 2400 + 10 x
\n" ); document.write( "0 x -10 x = -6000 + 2400
\n" ); document.write( "-10 x = -3600
\n" ); document.write( "/ -10
\n" ); document.write( "x = 360 ml Water
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\n" ); document.write( "m.ananth@hotmail.ca
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