document.write( "Question 1033593: Ricky adds 11L of water to a 60.5% solution of alcohol in water. If the new concentration is 36.3%, how much was the original solution?\r
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document.write( "A. 5.5 l
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document.write( "B. 11 L
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document.write( "C. 16.5 L
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document.write( "D. 22 L \n" );
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Algebra.Com's Answer #648258 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Ricky adds 11L of water to a 60.5% solution of alcohol in water. If the new concentration is 36.3%, how much was the original solution? \n" ); document.write( "--------------------- \n" ); document.write( "S = amount of 60.5% solution \n" ); document.write( "--- \n" ); document.write( "S*60.5 + 11*0 = (S + 11)*36.3 \n" ); document.write( "60.5S = 36.3S + 399.3 \n" ); document.write( "24.2S = 399.3 \n" ); document.write( "S = 16.5 liters\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |