document.write( "Question 1033581: The tens digits of a 2-digit number is 3 more than the ones digit. if the product of the number and the sum of its digits is 841, find the number.\r
\n" ); document.write( "\n" ); document.write( "This is what I did :)
\n" ); document.write( "Tens= x+3
\n" ); document.write( " DISABLED_event_Ones= x\r
\n" ); document.write( "\n" ); document.write( "Number is 10(x+3)+x
\n" ); document.write( " 10x+30+x
\n" ); document.write( " 11x+30
\n" ); document.write( "Sum of the digits 2x+3\r
\n" ); document.write( "\n" ); document.write( "So (11x+20)(2x+3) = 22x^2+93x-751=0 \r
\n" ); document.write( "\n" ); document.write( "I'm stuck there. I don't know what I did wrong..
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Algebra.Com's Answer #648225 by ikleyn(52781) $\"\"$ $\"About$

You can put this solution on YOUR website!
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document.write( "841 = 29*29 = .\r\n" );
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document.write( "This is the ONLY possible factoring of the number 841 in non-trivial smaller factors.\r\n" );
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document.write( "Do they satisfy the condition?   - Obviously, not.\r\n" );
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document.write( "What is the conclusion? - The conclusion is: the condition is wrong.\r\n" );
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