document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=89161>Question 89161</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0073022446/algebrahomeworkh>INTERMEDIATE ALGEBRA</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Use the Binomial Theorem to write out and simplify the first four terms in the expansion of the (2a+3b)^7. \r<BR>\n" );
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document.write( "Simplifying a term means to remove all parentheses and evaluate binomial coefficients. For example, the 3rd term of (2a+3b)^7  is given below in simplified form.  <BR>\n" );
document.write( "Third term = (7 over 2)(2a)^5(3b)^2=21*2^5a^5*2^2b^2= 6048a^5b^2<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64822 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64822\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the Binomial Theorem to write out and simplify the first four terms in the expansion of the (2a+3b)^7. <BR>\n" );
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document.write( "7C7(2a)^7 + 7C6(2a)^6(3b) + 7C5(2a)^5(3b)^2 + 7C4(2a)^4(3b)^3\r<BR>\n" );
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document.write( "= 128a^7 + 7(64a^6)(3b) + 21(32a^5)(9b^2) + 35(16a^4)(27b^3)\r<BR>\n" );
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document.write( "= 128a^7 + 1344a^6b + 6048a^5b^2 + 15120a^4b^3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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