document.write( "Question 1033411: From a Putnam competition:\r
\n" ); document.write( "\n" ); document.write( "Evaluate the integral \"int%28ln%28x%2B1%29%2F%28x%5E2%2B1%29%2C+dx%2C+0%2C1%29\".
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Algebra.Com's Answer #648219 by robertb(5830)\"\" \"About 
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Since \"dtan%5E-1%28x%29+=+dx%2F%281%2Bx%5E2%29\", \r
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\n" ); document.write( "\n" ); document.write( "Let \"w+=+tan%5E-1%28x%29\". ==> tanw = x. Now if x = 0, w = 0, and when x = 1, \"w+=+pi%2F4\".\r
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\n" ); document.write( "\n" ); document.write( "Now \r
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\n" ); document.write( "\n" ); document.write( "=\r
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\n" ); document.write( "\n" ); document.write( "But by using the substitution \"z+=+pi%2F4+-+w\" on the left integral.\r
\n" ); document.write( "\n" ); document.write( "Hence
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