document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033525>Question 1033525</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the sum, if it exists.\r<BR>\n" );
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document.write( "32+16+8+...\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648163 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648163\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a geometric sequence with common ratio r = 16/32 = 1/2 = 0.5<BR>\n" );
document.write( "Take note that 8/16 = 1/2 = 0.5<BR>\n" );
document.write( "You can take any term, but the first term, and divide it by its previous term. This will yield the common ratio. \r<BR>\n" );
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document.write( "The first term is a = 32.\r<BR>\n" );
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document.write( "The infinite sum S is equal to...\r<BR>\n" );
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document.write( "S = a/(1-r)\r<BR>\n" );
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document.write( "S = 32/(1-0.5) <font color=blue>Plug in a = 32 and r = 0.5</font>\r<BR>\n" );
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document.write( "S = 32/(0.5)\r<BR>\n" );
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document.write( "S = 64\r<BR>\n" );
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document.write( "So if you were to add up 32, 16, 8, ... and so on (going on forever following the same pattern), then the sum would be 64.\r<BR>\n" );
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document.write( "Final Answer: <font color=red>64</font> </SPAN>\n" );
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