document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033534>Question 1033534</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of a 70% acid solution must be added to 16 liters of a 10% acid solution to produce a 22% acid solution?\r<BR>\n" );
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document.write( "Please help me solve, thank you  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648159 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648159\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the amount of liters of 70% solution needed. Then:<BR>\n" );
document.write( ".7x + .10(16)=.22(16+x)<BR>\n" );
document.write( ".7x + 1.6=3.52+.22x<BR>\n" );
document.write( ".48x=1.92<BR>\n" );
document.write( "x=1.92/.48=4 liters of 70% acid needed to produce 20 liter of 22% solution!!!!!!!!<BR>\n" );
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