document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033514>Question 1033514</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a chemist needs 110 milliliters of an 80% solution but has only 76% and 98% solutions available.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648141 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648141\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the amount of solution at 76% be x. Then, the amount of solution at 98% will be 110-x since 110 is the total quantity desired.<BR>\n" );
document.write( "0.76x+0.98(110-x)= 0.80(110)<BR>\n" );
document.write( "0.76x+107.8-0.98x = 88<BR>\n" );
document.write( "-0.22x = -19.8 Divide both sides by -0.22 and remember that -/- = +<BR>\n" );
document.write( "x = 90<BR>\n" );
document.write( "You need 90ml of 76% and 110-90 = 20 ml of the 98% </SPAN>\n" );
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