document.write( "Question 1033438: A tourist boat makes trips both upriver and downriver from its mooring. The downriver trip is 36 km each way and takes 8 hours for the round trip. The upriver destination is 60 km away and it takes 10 hours to get there. Find the speed of the boat in still water and the speed of the river. \n" ); document.write( "
Algebra.Com's Answer #648087 by josgarithmetic(39617)\"\" \"About 
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The description is of two problems. The tourist boat is doing two round trips. This is a data table for the 36 distance trip which is a 72 km round trip. The 60 km, 10 one-way is a separate problem and should be simpler to solve.\r
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document.write( "                     speed       time        distance\r\n" );
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document.write( "Going, downriver      r+c        36/(r+c)    36\r\n" );
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document.write( "Return, upriver       r-c        36/(r-c)    36\r\n" );
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document.write( "TOTAL                            8
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\n" ); document.write( "\n" ); document.write( "Basic Rates Rule and sum of times gives \"36%2F%28r%2Bc%29%2B36%2F%28r-c%29=8\", and you will need the other part of the description to analyze and them form an additional equation. You will have two equations then, and two unknowns of r and c.\r
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document.write( "                   RATE      TIME       DISTANCE\r\n" );
document.write( "GOING (UPRIVER)    r-c       10          60\r\n" );
document.write( "RETURN             r+c      not needed not given\r\n" );
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\n" ); document.write( "\"%28r-c%29%2A10=60\"\r
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\n" ); document.write( "\n" ); document.write( "System of equations to solve is \"system%2836%2F%28r%2Bc%29%2B36%2F%28r-c%29=8%2C10%28r-c%29=60%29\".
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