document.write( "Question 1033432: Tom and John are speed skaters. Tom skates at a rate of 44 ft/sec and John skates at a rate of 50 ft/sec. If John is 120 ft behind of Tom when they start speed skating, how long will it take John to catch up to Tom? \n" ); document.write( "
Algebra.Com's Answer #648062 by ikleyn(52847)\"\" \"About 
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\n" ); document.write( "Tom and John are speed skaters. Tom skates at a rate of 44 ft/sec and John skates at a rate of 50 ft/sec.
\n" ); document.write( "If John is 120 ft behind of Tom when they start speed skating, how long will it take John to catch up to Tom?
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\n" ); document.write( "\n" ); document.write( "This way:\r
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document.write( "Let  t = time to catch up; then\r\n" );
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document.write( "44t + 120 = 50t\r\n" );
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document.write( "6t=120\r\n" );
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document.write( "t= \"120%2F6\" = 20 seconds before John catches up to Tom.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Or this way:\r
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document.write( "t = \"120%2F%2850-44%29\" = \"120%2F6\" = 20 seconds.\r\n" );
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document.write( "The numerator is the initial distance between them, while the denominator is a relative speed.\r\n" );
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\n" ); document.write( "\n" ); document.write( "For details, see a similar solved problem in the lesson Travel and Distance problems in this site.\r
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