document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033433>Question 1033433</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much pure water must be added to 4.5 litres of 87% acid solution to dilute it to 64% solution ?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648061 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648061\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the water is pure, then it is 100% water. We start out with an 87% acid solution, so:<BR>\n" );
document.write( "4.5(.87)+ X(1.0)=.64(4.5+X)<BR>\n" );
document.write( "3.915+X=2.88+.64X<BR>\n" );
document.write( "1.035=.64X<BR>\n" );
document.write( "X=1.035/.64=1.6172 liters of pure water needed to add to the mixture to make it 64% acid!!!!<BR>\n" );
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