document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1028977>Question 1028977</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A ski resort can manufacture enough snow to open its steepest run in 16 h, whereas naturally falling snow would have to last for 48 h to provide enough snow. If the resort makes snow at the same time as it is snowing naturally, how long will it be before the run can be opened? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648049 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648049\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> t/16 is the rate the resort makes snow,<BR>\n" );
document.write( "t/48 is the rate for naturally falling snow.<BR>\n" );
document.write( "If it is snowing, AND the resort is making snow, then<BR>\n" );
document.write( "1/16+1/48=1/t<BR>\n" );
document.write( "3/48+1/48=1/t<BR>\n" );
document.write( "4/48=1/t<BR>\n" );
document.write( "4t=48<BR>\n" );
document.write( "t=12 hours to make enough snow, working together!!!!! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );