document.write( "Question 1033113: The container held the compound (As) sub four O sub 6
\n" ); document.write( "and What was the percentage by weight of the Arsenic in this compound (As, 75;O,16)
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Algebra.Com's Answer #647996 by KMST(5328)\"\" \"About 
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The formula of the compound is \"As%5B4%5D\"\"O%5B6%5D\" , meaning that a molecule or formula unit comprises \"4\" atoms of \"As\" , and \"6\" atoms of \"O\" .
\n" ); document.write( "The mass of the \"4\" atoms of \"As\" ,
\n" ); document.write( "each with a mass of \"75\" atomic mass units, adds up to
\n" ); document.write( "\"4%2A75=300\" .
\n" ); document.write( "The mass of the \"6\" atoms of \"O\" ,
\n" ); document.write( "each with a mass of \"16\" atomic mass units, adds up to
\n" ); document.write( "\"6%2A16=96\" .
\n" ); document.write( "The total mass of the molecule is \"300%2B96=396\" atomic mass units,
\n" ); document.write( "and out of that total, the mass of the arsenic is
\n" ); document.write( "\"300\" atomic mass units.
\n" ); document.write( "As a fraction, that is
\n" ); document.write( "\"300%2F396=about0.76=about76%2F100=about76%25\" (rounding to whole numbers, or 2 significant figures, as a chemistry teacher might say).
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