document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033345>Question 1033345</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the clays saved $3000 for their vacation, this includes $900 for travel ad $80 per day for miscellaneous, write an inequality which represents the number of days X, the family can stay on vacation </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #647989 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=647989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> budget is 3000.<BR>\n" );
document.write( "cost is 900 plus 80 per day.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "900 + 80x must be less than  or equal to 3000.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "alternatively, 3000 must be greater than or equal to 900 + 80x.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "that leads to the equation 3000 >= 900 + 80x.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "subtract 900 from both sides of this equation to get 3000 - 900 >= 80x\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "divide both sides of this equation by 80 to get (3000 - 900) / 80 >= x\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "solve for x to get x <= 26.25.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "round down because you can't have a partial day, and your answer is that the number of days they can spend on vacation is less than or equal to 26.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "if 26 days, the total cost is 900 + 80 * 26 = 2980.<BR>\n" );
document.write( "if 27 days, the total cost is 2980 + 80 = 3060.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "at 27 days they are over budget.<BR>\n" );
document.write( "at 26 days they are under budget.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "most number of days is 26.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );