document.write( "Question 89151: A university bookstore recently sold a wirebound graph-paper notebook for $2.50, and a college-ruled notebook for $2.30. At the start of spring semester, a combination of 50 of these notebooks were sold for a total of $118.60. How many of each type were sold?\r
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\n" ); document.write( "\n" ); document.write( "A shopper buys three oranges and five lemons for $10.26, while a second shopper buys four lemons and six oranges for $11.16. What is the price of each fruit?\r
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\n" ); document.write( "\n" ); document.write( " can i please get help with these word problems?
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Algebra.Com's Answer #64796 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A university bookstore recently sold a wirebound graph-paper notebook for $2.50, and a college-ruled notebook for $2.30. At the start of spring semester, a combination of 50 of these notebooks were sold for a total of $118.60. How many of each type were sold?
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\n" ); document.write( "Let x = no. of graph notebooks; Let y = no. of ruled notebooks
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\n" ); document.write( "The number of items equation:
\n" ); document.write( "x + y = 50
\n" ); document.write( "or
\n" ); document.write( "x = (50 - y); use for substitution
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\n" ); document.write( "The $$ amt equation:
\n" ); document.write( "2.50x + 2.30y = 118.60
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\n" ); document.write( "Substitute (50-y) for x, solve for y:
\n" ); document.write( "2.50(50-y) + 2.30y = 118.60
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\n" ); document.write( "125 - 2.5y + 2.3y = 118.60
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\n" ); document.write( "-2.5y + 2.3y = 118.6 - 125
\n" ); document.write( "-.2y = -6.4
\n" ); document.write( "y = -6.4/-.2
\n" ); document.write( "y = 32 ruled note books
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\n" ); document.write( "x = 50 - y
\n" ); document.write( "x = 50 -32
\n" ); document.write( "x = 18 graph note books
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\n" ); document.write( "Check solution using $$ equation
\n" ); document.write( "2.5(18) + 2.3(32) = 118.6
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\n" ); document.write( "A shopper buys three oranges and five lemons for $10.26, while a second shopper
\n" ); document.write( " buys four lemons and six oranges for $11.16. What is the price of each fruit?
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\n" ); document.write( "Let x = price of oranges; Let y = price of lemons
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\n" ); document.write( "Shopper 1 equation
\n" ); document.write( " 3x + 5y = 10.26
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\n" ); document.write( "Shopper 2 equation
\n" ); document.write( " 6x + 4y = 11.16
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\n" ); document.write( "Multiply eq1 by 2 and subtract eq2 from it:
\n" ); document.write( "6x + 10y = 20.52
\n" ); document.write( "6x + 4y = 11.16
\n" ); document.write( "------------------subtracting eliminates x
\n" ); document.write( "0x + 6y = 9.36
\n" ); document.write( "y = 9.36/6
\n" ); document.write( "y = 1.56 is the price of the lemons
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\n" ); document.write( "Find x using eq1, substitute 1.56 for y:
\n" ); document.write( "3x + 5(1.56) = 10.26
\n" ); document.write( "3x + 7.80 = 10.26
\n" ); document.write( "3x = 10.26 - 7.80
\n" ); document.write( "3x = 2.46
\n" ); document.write( "x = 2.46/3
\n" ); document.write( "x = .82 is the price of oranges
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\n" ); document.write( "Check solutions using eq2
\n" ); document.write( "6(.82) + 4(1.56) = 11.16
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\n" ); document.write( "Did this make sense to you, any questions?
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