document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033370>Question 1033370</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose a not equal to 0. Compute log_(2^a) 2^b in terms of a and b. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #647956 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=647956\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Compute log_(2^a) 2^b in terms of a and b. <BR>\n" );
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document.write( "Use the change of base Law:<BR>\n" );
document.write( "log(2^b)/log(2^a)<BR>\n" );
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document.write( "Use the power Law::<BR>\n" );
document.write( "b*log(2)/a*log(2)<BR>\n" );
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document.write( "= b/a<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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