document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033350>Question 1033350</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A coffee distributor needs to mix a(n) Rift Valley coffee blend that normally sells for $8.00 per pound with a Mexican Shade Grown coffee blend that normally sells for $10.40 per pound to create 20 pounds of a coffee that can sell for $8.12 per pound. How many pounds of each kind of coffee should they mix?<BR>\n" );
document.write( "A) Write an equation using the information as it is given above that can be solved to answer the question. Use x as your variable to represent the quantity of Rift Valley coffee blend.<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "They must mix <BR>\n" );
document.write( " pounds of the Rift Valley Blend <BR>\n" );
document.write( "pounds of the Mexican Shade Grown Blend. <BR>\n" );
document.write( "Round your answers to the nearest whole number of pounds. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #647940 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=647940\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A coffee distributor needs to mix a(n) Rift Valley coffee blend that normally sells for $8.00 per pound with a Mexican Shade Grown coffee blend that normally sells for $10.40 per pound to create 20 pounds of a coffee that can sell for $8.12 per pound. \r<BR>\n" );
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document.write( "How many pounds of each kind of coffee should they mix?<BR>\n" );
document.write( "Quantity Eq:: e + t = 20 lbs<BR>\n" );
document.write( "Value Eq:::: 8e + 10.4t = 8.12*20<BR>\n" );
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document.write( "8e + 8t = 8*20<BR>\n" );
document.write( "8e + 10.4t = 162.4<BR>\n" );
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document.write( "Subtract and solve for \"t\":<BR>\n" );
document.write( "2.4t = 2.4<BR>\n" );
document.write( "t = 1 lb (amt. of $10.40 coffee needed)<BR>\n" );
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document.write( "e = 20-1 = 19 lb (amt. of $8 coffee needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "------------\r<BR>\n" );
document.write( "<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );