document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033301>Question 1033301</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If cos(theta) = sqrt(2)/-3 and theta has its terminal side in Quadrant 2, find the exact value of tan(2theta) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #647896 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=647896\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  If cos(theta) = sqrt(2)/-3 and theta has its terminal side in Quadrant 2, find the exact value of tan(2theta) <BR>\n" );
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document.write( "Since cos = x/r and since x is negative in QII, x = -sqrt(2) and r = 3<BR>\n" );
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document.write( "Then y = sqrt[3^2-(sqrt(2))^2] = sqrt(7)<BR>\n" );
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document.write( "tan = y/x = -sqrt(7)/sqrt(2) = -sqrt(7/2)<BR>\n" );
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document.write( "Ans: Formula:: tan(2t) = 2tan(x)/(1-tan^2(x))<BR>\n" );
document.write( "Your Problem:<BR>\n" );
document.write( "tan(2t) = 2[-sqrt(7/2)]/[1-(7/2)] -2sqrt(7/2)/(-5/2) = (4/5)sqrt(7/2)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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