document.write( "Question 1033235: Find the ratio of the area of the smaller circle to the area of the larger circle.
\n" ); document.write( "Picture: Circle inscribed in a square inscribed in a bigger circle.
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Algebra.Com's Answer #647892 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "From the diagram,
\n" ); document.write( "\"R%5B1%5D=S%2F2\"
\n" ); document.write( "and
\n" ); document.write( "\"%28S%2F2%29%5E2%2B%28S%2F2%29%5E2=R%5B2%5D%5E2\"
\n" ); document.write( "\"S%5E2%2F4%2BS%5E2%2F4=R%5B2%5D%5E2\"
\n" ); document.write( "\"S%5E2%2F2=R%5B2%5D%5E2\"
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\n" ); document.write( "In terms of area,
\n" ); document.write( "\"A%5B1%5D=pi%2AR%5B1%5D%5E2\"
\n" ); document.write( "\"A%5B1%5D=pi%2A%28S%2F2%29%5E2\"
\n" ); document.write( "\"A%5B1%5D=pi%2A%28S%5E2%2F4%29\"
\n" ); document.write( "\"A%5B1%5D=%28pi%2F4%29S%5E2\"
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\n" ); document.write( "\"A%5B2%5D=pi%2AR%5B2%5D%5E2\"
\n" ); document.write( "\"A%5B2%5D=pi%2A%28S%5E2%2F2%29\"
\n" ); document.write( "\"A%5B2%5D=%28pi%2F2%29S%5E2\"
\n" ); document.write( "So then,
\n" ); document.write( "\"A%5B2%5D=2A%5B1%5D\"
\n" ); document.write( "\"A%5B2%5D%2FA%5B1%5D=2\"
\n" ); document.write( "\"highlight%28A%5B1%5D%2FA%5B2%5D=1%2F2%29\"
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