document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033309>Question 1033309</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 4 times as large as another. The sum of their reciprocals is 35/4. Find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #647881 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=647881\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  One number is 4 times as large as another. The sum of their reciprocals is 35/4. Find the two numbers. <BR>\n" );
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document.write( "a = 4b<BR>\n" );
document.write( "(1/a) + (1/b) = 35/4<BR>\n" );
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document.write( "Substitute for \"a\" and solve for \"b\"::<BR>\n" );
document.write( "1/(4b) + 1/b = 35/4<BR>\n" );
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document.write( "Multiply thru by 4b to get:<BR>\n" );
document.write( "1 + 4 = 35b<BR>\n" );
document.write( "b = 5/35 = 1/7<BR>\n" );
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document.write( "a = 4b = 4/7<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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