document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033214>Question 1033214</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the number of terms in the following arithmetic sequence...\r<BR>\n" );
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document.write( "3a-5, a+1, 7-a,..., 109-35a<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #647872 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=647872\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3a-5, a+1, 7-a,..., 109-35a\r<BR>\n" );
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document.write( "first term = 3a-5\r<BR>\n" );
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document.write( "d= (a+1)-(3a-5) = -2a+6\r<BR>\n" );
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document.write( "tn = 109-35a\r<BR>\n" );
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document.write( "109-35a = (3a-5)+(n-1)(-2a+6)\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2838%283-a%29%29%2F%282%283-a%29%29=n-1 ALIGN=MIDDLE  ALT=\"%2838%283-a%29%29%2F%282%283-a%29%29=n-1\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "n=20 </SPAN>\n" );
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