document.write( "Question 1033227: A woman can bicycle 88 miles in the same time as it takes her to walk 16 miles. She can ride 9 mph faster than she can walk. How fast can she walk?
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Algebra.Com's Answer #647843 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Assign variables and make a data table.\r
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document.write( "             RATE        TIME        DISTANCE\r\n" );
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document.write( "BICYCLE      r+9          t           88\r\n" );
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document.write( "WALK         r            t           16
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\n" ); document.write( "\n" ); document.write( "Basic travel rates rule is RT=D to relate speed, time, and distance.\r
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\n" ); document.write( "\n" ); document.write( "Make the system of equations.
\n" ); document.write( "\"system%28%28r%2B9%29t=88%2Crt=16%29\"\r
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\n" ); document.write( "\n" ); document.write( "The number t is the same for both equations, and you are interested in finding r.
\n" ); document.write( "\"system%28t=88%2F%28r%2B9%29%2Ct=16%2Fr%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"88%2F%28r%2B9%29=16%2Fr\"\r
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\n" ); document.write( "\n" ); document.write( "\"88r=16%28r%2B9%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"88r=16r%2B16%2A9\"\r
\n" ); document.write( "\n" ); document.write( "\"44r=8r%2B8%2A9\"\r
\n" ); document.write( "\n" ); document.write( "\"11r=2r%2B2%2A9\"\r
\n" ); document.write( "\n" ); document.write( "\"9r=2%2A9\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28r=2%29\"
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