document.write( "Question 1033266: the evidence of an illegal gun operation consisted of two different types of guns. the pistols are worth $565 a piece and the rifles are worth $795 a piece. If there are two times as many rifles as there are pistols, and all the guns combined are worth $75,425, how many rifles and pistols are being held in evidence? \n" ); document.write( "
Algebra.Com's Answer #647828 by addingup(3677)![]() ![]() You can put this solution on YOUR website! R=2P \n" ); document.write( "565P+795(2P)=75425 \n" ); document.write( "565P+1590P=75425 \n" ); document.write( "2155P=75425 \n" ); document.write( "P=75425/2155 35 and R=2(35)=70 \n" ); document.write( "^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ \n" ); document.write( "John \n" ); document.write( " |