document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033255>Question 1033255</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Kellen&#8203;'s boat travels 12 mph. Find the rate of the river current if she can travel 6mi upstream in the same amount of time she can go 10mi downstream.(let x = rate of the current) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #647806 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=647806\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> distance = rate*time<BR>\n" );
document.write( "Let x = rate of the current (this is what the problem says)<BR>\n" );
document.write( "6/(12-x) = 10/(12+x)<BR>\n" );
document.write( "cross multiply:<BR>\n" );
document.write( "72+6x = 120-10x <BR>\n" );
document.write( "16x = 48<BR>\n" );
document.write( "x = 3 this is the speed of the current. </SPAN>\n" );
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