document.write( "Question 1033247: please help me solve: If the length of a rectangle is 2 more than its width, and its area is 35 square feet, what are the measures of the length and width? \n" ); document.write( "
Algebra.Com's Answer #647800 by addingup(3677)![]() ![]() You can put this solution on YOUR website! begin with the formula for the area \n" ); document.write( "L*W = area \n" ); document.write( "And the problem says: \n" ); document.write( "L = W+2 \n" ); document.write( "So now we have: \n" ); document.write( "(W+2)*W = 35 \n" ); document.write( "W^2+2W-35 = 0 \n" ); document.write( "(W-5)(W+7)= 0 \n" ); document.write( "Split into 2 equations: \n" ); document.write( "W-5 = 0 \n" ); document.write( "or \n" ); document.write( "W+7 = 0 \n" ); document.write( "W = 5 \n" ); document.write( "or \n" ); document.write( "W= -7 We know we're looking for a positive number, so toss this one out. Your answer is: \n" ); document.write( "W = 5 \n" ); document.write( "````````````````````````````````````````````````` \n" ); document.write( "Check: \n" ); document.write( "(5+2)*5 = 35 \n" ); document.write( "7*5 = 35 Correct \n" ); document.write( "John \n" ); document.write( " \n" ); document.write( " |