document.write( "Question 1033173: How many g of gold should a coin of 45 % gold be if when combined with a 11 g pure gold necklace, it forms a metal that is 71 % gold? \n" ); document.write( "

Algebra.Com's Answer #647736 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+x+\"$ = grams of the 45% gold coin needed
\n" ); document.write( " $\"+.45x+\"$ = grams of pure gold in $\"+x+\"$
\n" ); document.write( "grams of 45% gold coin
\n" ); document.write( "-----------------------
\n" ); document.write( " $\"+%28+.45x+%2B+11+%29+%2F+%28+x+%2B+11+%29+=+.71+\"$
\n" ); document.write( " $\"+.45x+%2B+11+=+.71%2A%28+x+%2B+11+%29+\"$
\n" ); document.write( " $\"+.45x+%2B+11+=+.71x+%2B+7.81+\"$
\n" ); document.write( " $\"+.26x+=+3.19+\"$
\n" ); document.write( " $\"+x+=+12.27+\"$
\n" ); document.write( "12.27 grams of the 45% gold coin are needed
\n" ); document.write( "---------------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+.45x+%2B+11+%29+%2F+%28+x+%2B+11+%29+=+.71+\"$
\n" ); document.write( " $\"+%28+.45%2A12.27+%2B+11+%29+%2F+%28+12.27+%2B+11+%29+=+.71+\"$
\n" ); document.write( " $\"+%28+5.522+%2B+11+%29+%2F+23.27+=+.71+\"$
\n" ); document.write( " $\"+16.52+%2F+23.27+=+.71+\"$
\n" ); document.write( " $\"+.7099+=+.71+\"$
\n" ); document.write( "close enough \n" ); document.write( "

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